Question

• Express each of the following in exponential form:

$1. \: ( \frac{-5}{7}) \times ( \frac{ - 5}{7}) \times ( \frac{ - 5}{7}) \times ( \frac{ - 5}{7})$
$2. \: - 5 \times - 5 \: \times \: - 5 \: \times - 5$
$3. \: x \times x \times x \times x \times a \times a \times b \times b \times b$
$4. \: ( - 2) \times ( - 2) \times ( - 2) \times ( - 2) \times a \times a \times a$
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Answer 1

Answer:

1. (-5/7)^4

2.(-5)^4

Step-by-step explanation:

hope it's helpful

Answer 2

Answer:

$(\frac{-5}{7} )\times (\frac{-5}{7} )\ \times (\frac{-5}{7} ) \times (\frac{-5}{7} ) = (\frac{-5}{7} )^4$

$-5 \times -5 \times -5 \times -5 = (-5)^4$

$x \times x \times x \times x \times a \times a \times b \times b \times b = x^4a^2b^3$

$(-2) \times (-2) \times (-2) \times (-2) \times a \times a \times a=(-2)^4 a^3$

Step-by-step explanation:

Formula:

$a \times a \times a ----n = a^ n$

$(\frac{-5}{7} )\times (\frac{-5}{7} )\ \times (\frac{-5}{7} ) \times (\frac{-5}{7} ) = (\frac{-5}{7} )^4$

$-5 \times -5 \times -5 \times -5 = (-5)^4$

$x \times x \times x \times x \times a \times a \times b \times b \times b = x^4a^2b^3$

$(-2) \times (-2) \times (-2) \times (-2) \times a \times a \times a=(-2)^4 a^3$