Express each of the following in terms of angles between 0° and 45°
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please solve all three with steps and Don't give irrevelent answers
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(1) sin 59° + tan 63°
= sin(90-31) + tan(90-27)
=cos 31 + cot 27
(2) cosec 68° + cot 72°
= cosec(90-22) + cot(90-18)
= sec 22 + tan 18
(3) cos 74° + sec 67°
=cos(90-16) + sec(90-23)
=sin 16 + cosec 23
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Answer:
1) sin 59⁰ + tan 63⁰
= sin (90-31) + tan (90-27)
= cos 31⁰ + cot 27⁰
2) cosec 68⁰ + cot 72⁰
=cosec (90-22) + cot (90-18)
= sec 22⁰ + tan 18⁰
3) cos 74⁰ + sec 67⁰
= cos (90-16) + sec (90-23)
= sin 16⁰ + cosec 23⁰
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