Question

Express each of the following linear equation in two variables in

the form of ax + by + c = 0 and write the values of a, b and c.

(i) 2x + 3y = 5 (ii) x = -5 + 3y

(iii) ey = 2x (iv)y = 9

(v)x/3 – y/4 = 2 (vi)12y – 1/3 = x​

Answer 1

Hey Pretty Stranger!

Here we've to express these linear equations in the form of ax + by + c = 0 and hence to write the values of a,b and c

$\sf \: i) \: 2x \: + 3y = 5$

$\sf \longrightarrow 2x + 3y - 5 = 0 \:$

$\boxed{ \purple{ \sf a \: = 2}} \: \: \: \boxed{ \purple{ \sf b \: = 3}} \: \sf \: and \: \boxed{ \purple{ \sf c \: = - 5}} \:$

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$\sf \: ii) \: x = - 5 + 3y$

$\sf \longrightarrow x - 3y + 5 = 0$

$\boxed{ \purple{ \sf a \: = 1}} \: \: \: \boxed{ \purple{ \sf b \: = - 3}} \: \sf \: and \: \boxed{ \purple{ \sf c \: = 5}} \:$

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$\sf \: iii) \: y = 2x$

$\sf \longrightarrow - 2x + y +0 = 0$

$\boxed{ \purple{ \sf a \: = - 2}} \: \: \: \boxed{ \purple{ \sf b \: = 1}} \: \sf \: and \: \boxed{ \purple{ \sf c \: = 0}} \:$

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$\sf \: iv) \: \dfrac{x}{3} - \dfrac{y}{4} = 2$

$\sf \longrightarrow \dfrac{x}{3} - \dfrac{y}{4} - 2 = 0$

$\boxed{ \purple{ \sf a \: = \frac{1}{3} }} \: \: \: \boxed{ \purple{ \sf b \: = \frac{-1}{4} }} \: \sf \: and \: \boxed{ \purple{ \sf c \: = - 2}} \:$

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$\sf \: v) \: 12y - \dfrac{1}{3} = x$

$\sf \longrightarrow - x + 12y - \dfrac{1}{3} = 0$

$\boxed{ \purple{ \sf a \: = - 1 }} \: \: \: \boxed{ \purple{ \sf b \: = 12}} \: \sf \: and \: \boxed{ \purple{ \sf c \: = \frac{ - 1}{3} }} \:$