Express each of the following numbers as a product of Prime factors:
a. 500
b. 1372
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Solution
500 = 5 x 5 x 5x2x2
* In the above prime factorisation 2 x2 remain after grouping the prime factors in
triples.
5/ 500
5/100
5/20
2/4
5/2
/1
We have 1372 = 2 x 2 x 7 x 7 x7
Since, the prime factor 2 does not appear in a group of triples.
21372
2686
7343
749
77
1
.. 1372 is not a perfect cube.
Obviously, to make it a perfect cube we need one
more 2 as its factor.
i.e.
or
[1372] x 2 = [2 x 2x7x7x7] x2
2744 = 2 x 2 x2x7x7x7
which is a perfect cube.
Thus, the required smallest number = 2.
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