Question

Express for time period of simple pendulum/. Centripetal force using homogeneity of dimension

Answer 1

Answer:

A mass m suspended by a wire of length L is a simple pendulum and undergoes simple harmonic motion for amplitudes less than about 15º. The period of a simple pendulum is T=2π√Lg T = 2 π L g , where L is the length of the string and g is the acceleration due to gravity..Or, T = √[M0 L1 T0] × [M0 L1 T-2]-1 = √[T2] = [M0 L0 T1]. Therefore, the time period is dimensionally represented as [M0 L0 T1].

Explanation:

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