Express (i) 0.00323232.....and (ii) 2.0151515....... in the form of p/q, where p and q are integers and q not equal to 0. Can anybody do it ?
Answers
Answered by
134
In such problems the key is to eliminate the recurring values after the decimal. This can be achieved using the following method :-
1) Let x = 0.00323232.......(i)
Multiply equation (i) by 100 on both sides,
100 x = 0.323232.......(ii)
Multiply equation (i) by 10,000 on both sides,
10,000 x = 32.323232.......(iii)
Subtracting equation (ii) from (iii),
10,000 x = 32.323232.......(iii)
-- 100 x = 0.323232.......(ii)
________________________________
9900 x = 32
Thus, x = 32 / 9900
2) Let x = 2.0151515.......(i)
Multiply equation (i) by 1000 on both sides,
1000 x = 2015.1515.......(ii)
Multiply equation (i) by 10 on both sides,
10 x = 20.151515.......(iii)
Subtracting equation (iii) from (ii),
1000 x = 2015.1515.......(iii)
-- 10 x = 20.151515.......(ii)
________________________________
990 x = 1995
Thus, x = 1995 / 990
Therefore the p/q forms are 32 / 9900 and 1995 / 990
1) Let x = 0.00323232.......(i)
Multiply equation (i) by 100 on both sides,
100 x = 0.323232.......(ii)
Multiply equation (i) by 10,000 on both sides,
10,000 x = 32.323232.......(iii)
Subtracting equation (ii) from (iii),
10,000 x = 32.323232.......(iii)
-- 100 x = 0.323232.......(ii)
________________________________
9900 x = 32
Thus, x = 32 / 9900
2) Let x = 2.0151515.......(i)
Multiply equation (i) by 1000 on both sides,
1000 x = 2015.1515.......(ii)
Multiply equation (i) by 10 on both sides,
10 x = 20.151515.......(iii)
Subtracting equation (iii) from (ii),
1000 x = 2015.1515.......(iii)
-- 10 x = 20.151515.......(ii)
________________________________
990 x = 1995
Thus, x = 1995 / 990
Therefore the p/q forms are 32 / 9900 and 1995 / 990
Answered by
19
Answer:
the p/q forms are 32/9900 and 1995/990
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