Question

express (-i)(2i)(-1/8i)^3 in the form of a+ib​

Answer 1

Answer:

Explanation:

-2i^2 = -2 * -1 = 2

(-1/8i)^3 = -1/512i^2 * i = 1/512i

1/256i = (-1*-1)/256i = (-i^2)/256i = -i/256

-i/256 = 0 + i(-1/256)

a = 0 and b = (-1/256)