Question

Express I raise to minus 41 in a + iB form​

Answer 1

Answer:

$i^{-41}=0+(-1)i$

Step-by-step explanation:

$i^{-41}$

$=\frac{1}{i^{41}}$

$=\frac{1}{i^{40}.i^1}$

using

$\boxed{i^{4n}=1}$

$=\frac{1}{i}$

using

$\boxed{i^2=-1\:\implies\:\frac{1}{i}=-i}$

$=-i$

$=0+(-1)i$