express i⁹+i¹⁹ in the form of a+ib
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Answer:
i
9
+i
19
=i(i
8
+i
18
)
=i((i
2
)
4
+(i
2
)
9
=i((−1)
4
+(−1)
9
)[∵i
2
=−1]
=i(1−1)
=i(0)
=0
=0+i(0)
Comparing with a+ib,
a=0, b=0
Ans 0+i(0)
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