express in a+ib form 4-3i / 1-i
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(4-3i)/(1-i)
=[(4-3i)(1+i)]/[(1-i)(1+i)]
=[4-3i+4i-3i^2]/[1-i^2]
=[4+i+3]/[1+1] [i^2=-1]
=[7+i]/2
=(7/2)+i(1/2) [ans]
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