express in a+ib from 3(7+7i)+i(7+i7)
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Answered by
2
Answer:
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Step-by-step explanation:
= 3(7+7i)+i(7+i7)
= 21+21i+7i+7i^2
= 21+28i+7i^2 answer
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Answered by
6
Answer:
The given complex number in the form of a + ib is 14 + 28i.
Step-by-step-explanation:
We have given a complex number.
We have to express it in the standard form.
The given complex number is 3 ( 7 + 7i ) + i ( 7 + i7 ).
We know that,
The standard form of a complex number is a + ib; a, b are real numbers and i² = - 1.
Now,
3 ( 7 + 7i ) + i ( 7 + i7 )
⇒ 21 + 21i + i ( 7 + 7i )
⇒ 21 + 21i + 7i + 7i²
⇒ 21 + 28i + 7 * ( - 1 )
⇒ 21 + 28i - 7
⇒ 21 - 7 + 28i
⇒ 14 + 28i
∴ The given complex number in the form of a + ib is 14 + 28i.
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