Question

Express in exponential​

Answer 1

Step-by-step explanation:

$\frac{ {(18)}^{4} \times {(9)}^{5} \times 4 }{ {(6)}^{3} \times {(8)}^{3} \times {(81)}^{4} } \\ = \frac{ {(2 \times {3}^{2} )}^{4} \times {( {3}^{2} )}^{5} \times {2}^{2} }{ {(2 \times 3)}^{3} \times {( {2}^{3} )}^{3} \times {( {3}^{4} )}^{4} } \\ = \frac{ {2}^{4} \times {3}^{8} \times {3}^{10} \times {2}^{2} }{ {2}^{3} \times {3}^{3} \times {2}^{9} \times {3}^{16} } \\ = \frac{ {2}^{4 + 2} \times {3}^{8 + 10} }{ {2}^{3 + 9} \times {3}^{3 + 16} } \\ = \frac{ {2}^{6} \times {3}^{18} }{ {2}^{12} \times {3}^{19} } \\ = {2}^{6} \times {3}^{18} \times {2}^{ - 12} \times {3}^{ - 19} \\ = {2}^{6 - 12} \times {3}^{18 - 19} \\ = {2}^{ - 6} \times {3}^{ - 1} \\ = \frac{1}{ {2}^{6} \times 3}$

Hope you get your answer