Question

Express in significant figures the mass of 20.0 cm3 of a liquid having density of 1.438 gm

cm -3​

Answer 1

Answer:

3.3

Explanation:

Mass of the substance m=49.53g

Volume of the substance V=1.5cm

3

Density of the substance d=

V

m

∴ d=

1.5

49.53

=33.02gcm

−3

As 49.53 has four significant figures whereas 1.5 has two significant figures.

Thus, the value of the density of the substance must have two significant figures.

Thus, the density of the substance d=3.3gcm

−3

.