Question

Express in simplest form (a) 2/3 + 1/6 (b) 3/4 + 5/8​

Answer 1

Step-by-step explanation:

$(a) \: \dfrac{2}{3} + \dfrac{1}{6}$

Take LCM = 6

$= \dfrac{2 \times 2}{3 \times2} + \dfrac{1}{6}$

$\:$

$= \dfrac{4}{6} + \dfrac{1}{6}$

$\:$

$= \dfrac{4 + 1}{6}$

$\:$

$= \boxed{\dfrac{5}{6}.}$

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$(b)\:\dfrac{3}{4} + \dfrac{5}{8}$

Take LCM = 8

$= \dfrac{3 \times 2}{4 \times 2} + \dfrac{5}{8}$

$\:$

$= \dfrac{6}{8} + \dfrac{5}{8}$

$\:$

$= \dfrac{6 + 5}{8}$

$\:$

$= \boxed{\dfrac{11}{8}= 1\dfrac{3}{8}}.$

Answer 2

Hi Mate ! Here are your Answers :

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1]

$\large\tt{ \frac{2}{3} + \frac{1}{6} }$

As we know, if the denominator are not same, we take their LCM and change the numerator according to it .

So, LCM of 3 and 6

= 6

$\large\tt{ hence \: \frac{2}{3} = \frac{2 \times 2}{3 \times 2}}$

$\large\implies \tt{ \frac{2}{3} = \frac{4}{6} }$

$\large\tt{and \: \frac{1}{6} = \frac{1}{6} }$

Hence,

$\large\tt{ \frac{1}{6} + \frac{2}{3} }$

$\large\tt{ = \frac{1}{6} + \frac{4}{6} }$

$\large\tt{ = \frac{4 + 1}{6} }$

$\red{ \underline{ \boxed{ \tt{ \implies \: \frac{1}{6} + \frac{2}{3} = \frac{5}{6} }}}}$

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2]

$\large{ \tt{ \frac{3}{4} + \frac{5}{8} }}$

As we know, here also the denominator are not same , so we will take there LCM .

LCM of 8 and 4

= 8

$\large\tt{ hence \: \frac{3}{4} = \frac{3 \times 2}{4 \times 2}}$

$\large\tt{ \implies \frac{3}{4} = \frac{6}{8} }$

$\large\tt{and \: \frac{5}{8} = \frac{5}{8} }$

Hence,

$\large\tt{ \frac{3}{4} + \frac{5}{8} }$

$\large\tt{ = \frac{6}{8} + \frac{5}{8}}$

$\large\tt{ = \frac{5 + 6}{8} }$

$\green{ \underline{ \boxed{\tt{ \implies \: \frac{3}{4} + \frac{5}{8} = \frac{11}{8}} }}}$

You can also write it as, (if you want) :

$\large\tt{ \frac{11}{8} = 1 \frac{3}{8} }$