Express in th eform a+ib (2-5i)(3+2i)
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Solution :
( 2 - 5i )( 3 + 2i )
= 2( 3 + 2i ) -5i( 3 + 2i )
= 6 + 4i - 15i - ( 5i )( 2i )
= 6 - 11i + 10
= 16 - 11i
= 16 + (-11)i [ a + ib form ]
Where , a = 16 , b = -11
••••
( 2 - 5i )( 3 + 2i )
= 2( 3 + 2i ) -5i( 3 + 2i )
= 6 + 4i - 15i - ( 5i )( 2i )
= 6 - 11i + 10
= 16 - 11i
= 16 + (-11)i [ a + ib form ]
Where , a = 16 , b = -11
••••
Answered by
2
( 2 - 5i )( 3 + 2i )
= 2( 3 + 2i ) -5i( 3 + 2i )
= 6 + 4i - 15i - ( 5i )( 2i )
= 6 - 11i + 10
= 16 - 11i
= 16 + (-11)i [ a + ib form ]
Where , a = 16 , b = -11
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