Express in the form A+iB: Log(-e)
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since from the Euler's equation we know that,
(cos€+isin€)=e^(i€)
=>e^(iπ)+1=0
=>e^(1+iπ)=-e. (multiplying both sides bye)
=>1+iπ=ln(-1)
(cos€+isin€)=e^(i€)
=>e^(iπ)+1=0
=>e^(1+iπ)=-e. (multiplying both sides bye)
=>1+iπ=ln(-1)
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