Question

express in the form of a+ib and write the values of a and b
(1+i)(1-i)^-1
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Answer 1

Answer:

a=0,b=1

Step-by-step explanation:

(1+i)/(1-i)

=(1+i)^2/(1)^2-(i)^2

=1+2*1*i+(i) ^2/1-(-1)

=1+2i+(-1)/1+1

=1+2i-1/2

=2i/2

=i

The standard form is a+ib

and we can write it as 0+i1

Therefore,a=0 and b=1