express in the standard form of linear equation in two variables x = 10 +7y /3
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After all the sulphur has burnt, remove the combustion spoon from the jar and put some water in the gas jar, cover it with a lid and shake it to dissolve sulphur dioxide gas. We will divide this solution in two parts and test it with blue litmus paper and red litmus paper
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Given that
Let us assume that the lowered temperature as negative,
Initial temperature = 40oC
Change in temperature per hour = -5oC
Change in temperature after 10 hours = (-5) × 10 = -50oC
∴The final room temperature after 10 hours of freezing process = 40oC + (-50oC)
= -10oC
The room temperature 10 hours after the process begins= -10oC
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