Question

Express into p /q form please riyaa didi solve this problem

Answer 1

Please post your question clearly :


(a) :

Let x = 1.32bar


As there 2 numbers under bar, multiply by 100


We get,

100x = 132.32 bar


Then, subtract x from both sides,

100x = 132.32 bar
_(-)x = __(-) 1.32 bar
99x = 131
________



$x = \frac{131}{99}$



Hence, 1.32 bar = 131/99

Answer 2

✴✴ Hey friends!!✴✴

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✴✴ Here is your answer↓⬇⏬⤵

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=> Q.no 1.) 1.32 bar on 2.

▶⏩ Let x = 1.3222...
[ Multiply both side by 10 ].

↪➡ 10 × x = 10 × 1.3222...

↪➡ 10x = 13.222................................(1).
[ Multiply both side by 10 ].

↪➡ 10 × 10x = 10 × 13.222...

↪➡ 100x = 132.222...........................(2).

▶⏩ Now,
→ Substract in equation (1) and (2).

↪➡ 100x - 10x = 132.222 - 13.222.

↪➡ 90x = 119.

↪➡ x = 119/90.✔✔.

=> Q.no. 2) 1.32 bar on 32.

▶⏩ Let x = 1.323232...........(1).
[ Multiply both side by 100].

↪➡ 100 × x = 100 × 1.323232...

↪➡ 100x = 132.323232.........(2).

▶⏩ Now,
→ Substract in equation (1) and (2).

↪➡ 100x - x = 132.323232 - 1.323232.

↪➡ 99x = 131.

↪➡ x = 131/99.✔✔.

=> Q. no 3). 1.32.

= 132/100.

= 33/25.✔✔.

✅✅ Hence, all the questions are in p/q form ✅✅.

✴✴ Thanks!!✴✴.

☺☺☺ Hope it is helpful for you ✌✌✌.