Express Log (-5) in terms of a+ib
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1
Answer:
(-5) in terms of a+ib is
1×-5+i×0
-5+i×0.
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Answer:
expression in the form of a + ib
(( 3 + i v5 ) ( 3 - iv5 ) ) / (( v3 + v2i ) - ( v3 - iv2 ))
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