Question

Express log 86 in terms of log 2 , log 3 and log 7

Answer 1

Answer

we know,86 = 2 × 43=> log86 = log(2×43)=> log86 = log2 × log 43

Again,

84 = 2×2×3×7=> log 84 = log(2×2×3×7)

=> log 84 = log 2 + log 2 + log 3 + log 7

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