express log(a²c/√b) in terms of log a,log b and log c
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Answer:
2loga+logc-1/2logb
Step-by-step explanation:
=loga^2c-log√b (loga/b=loga-logb)
=loga^2+logc-logb^1/2 (√=1/2)
=2loga+logc-1/2logb (loga^b=bloga)
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