Question

express n square as sum of two consecutive natural numbers

Answer 1

Answer:

Two consecutive numbers can be denoted by n and n+1, therefore, two consecutive square numbers are n^2 and (n+1)^2. If we subtract 1 from their sum we get: n^2 + (n+1)^2 -1 = n^2 + n^2 + 2n+1 -1 = 2n^2 + 2n = 2n(n+1).

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

When we add two consecutive numbers, we get an odd number. n + (n+1) = 2n+1. The converse statement: any odd number ≥ 3 can be written as the sum of two consecutive natural numbers.

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