Question

Express (p + p + 1) (p - p + 1) as a difference of two squares.​

Answer 1

Step-by-step explanation:

x^2 - Y^2 = (x+y)(x-y)

the above problem is reverse of this equation

Answer 2

Answer:

The answer is $p^{2} - (p+1)^{2}$

Step-by-step explanation:

According to the given question we take into consideration the suitable identity to solve this question. As we have been given here,

$(p + p + 1) ( p - p + 1)$

Here we are keen to use the identidy,

$(a+b)(a-b) = a^{2} - b^{2}$

Here a = p and b = p + 1

we have,

(p + p + 1) (p - p + 1) = $p^{2} - (p+1)^{2}$

Therefore it is the required answer.