Question

express root 7 as a irrational number

unnecessary answers will be reported and no spamming..​

Answer 1

Answer:

Hi!

√7 is irrational - i.e. it is impossible to find a value for 7–√ which can be represented as ab where a & b are integers.

To prove this :

Lets assume the opposite that n−−√ can be represented as ab , where a & b have no factors in common, and n is an integer (in mathematical language two values which have no common factors are termed co-prime)

n−−√=ab

so

n=a2b2

The only way this can be the case is if a2 and b2 have factors in common which can be canceled out (remember n is an integer); but we have already assumed that a & b have no common factors - and if a & b have no common factors, then a2 and b2 can’t have common factors either - with one exception if b (and b2 ) are equal to 1.

So the only way that

n−−√=ab

is if b is 1, and ∴ n is a perfect square.

Since we know that 7 is not a perfect square, then 7–√ must be irrational

Step-by-step explanation:

Hope this answer helped you and please rate my answer..

Answer 2

Answer:

Hii

Step-by-step explanation:

I think.....it helps you and stay home and stay safe