Question

express root3(cosπ/6+isinπ/6) in the form of x+iy​

Answer 1

Answer:

root3(π/6) will be ans

Answer 2

$\underline{\underline{ \bf{ {answer}}}} : - \\ \\ \underline{\underline{\blue{\bf{explanation}}}} : - \\ \\ \implies \: \sqrt{3} \bigg( \cos( \frac{ \pi}{6} ) + i \: \sin( \frac{ \pi}{6} ) \bigg) \\ \\ \because \: \star \: \cos( \frac{ \pi}{6} ) = \frac{ \sqrt{3} }{2} \\ \\ \: \: \: \: \: \star \: \sin( \frac{ \pi}{6} ) = \frac{1}{2} \\ \\ \therefore \\ \\ \implies \: \sqrt{3} \bigg( \frac{ \sqrt{3} }{2} + i \: \frac{1}{2} \bigg) \\ \\ \implies \: \frac{3}{2} + i \: \frac{ \sqrt{3} }{2}$

this is in the form of (x + i y)