express sec ^ 2 theta - tan 2 theta as a perfect square
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it's equal to 1, now you can write it ( sin^2 theta + cos^2 theta )^2
faisalhashmi:
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explain karo
Answered by
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sec^2 theta - tan^2theta is a perfect square if its square root has a whole number.
sec^2 theta - tan^2theta
=1/cos^2theta -sin^2theta/cos^2theta
=1-sin^2theta/cos^2theta
(But, 1-sin^2theta = cos ^2theta .)
= cos^2theta/cos^2theta =1.
square of (sec^2 theta - tan^2theta) = square roor(1) = 1, which is a perfect square.
Hence proved that it is a perfect square.
sec^2 theta - tan^2theta
=1/cos^2theta -sin^2theta/cos^2theta
=1-sin^2theta/cos^2theta
(But, 1-sin^2theta = cos ^2theta .)
= cos^2theta/cos^2theta =1.
square of (sec^2 theta - tan^2theta) = square roor(1) = 1, which is a perfect square.
Hence proved that it is a perfect square.
bhai questions kuch hai
kar rahe hai kuch tum
Excuse me Faisal
You have asked a question on how you should show that that expression is a perfect square and i have shown u the way on how to show that
In the above ,aashu has stated that 1 is a perfect square and hence that expression is a perfect square
I have shown u the way the expression became =1.
I am trying to help brother!
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