Question

Express sec 50° + cot 78° in terms of t-ratios of angles between 0° to 45°.

Answer 1

sec 50° +cot 78°= sec(90-40)+ cot(90-12)
= cosec 40°+tan 12°

Answer 2

Answer:

cosec 40°  + tan 12°

Step-by-step explanation:

Given :  

sec 50° + cot 78°

Since we know,

sec ( 90 - θ ) = cosec θ

cot ( 90 - θ ) = tan θ

We can write the given expression as,

sec ( 90° - 40°) + cot ( 90° - 12°)

So,

sec ( 90° - 40° ) = cosec 40°

cot ( 90° - 12° ) = tan 12°

Hence,

sec 50° + cot 78° in terms of t-ratios of angles between 0° to 45° can be written as : cosec 40°  + tan 12°