Express sec A and cos A in terms of sides of right angle triangle
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Answered by
3
Answer:
considering triangleABC==>
Step-by-step explanation:
secA= H/B
so, secA=AC/BC
cosA=B/H
so, cosA=BC/AC
Answered by
1
Hola mate
Here is your answer -
Plz refer to the attachments given..
Attachments:
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