Question

Express (sec²x-1) (cot²x)

Answer 1

$({sec}^{2} x - 1)( {cot}^{2} x) \\ = ( {tan}^{2} x)( {cot}^{2} x) \\ = \frac{1}{ {cot}^{2}x } \times {cot}^{2} x = 1$

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Answer 2

I feel my answer is correct for this question given