Question

Express
Sec79+Cot 79 interms of
trigonometric Ratios
of angles between 0 and 45​

Answer 1

Step-by-step explanation:

sec79 + cot79

=cosec(90-79) + tan(90-79)

=cosec11 + tan 11

.now the angle is between 0 and 45 i.e the angle is 11

Answer 2

Express  $\sec79+\cot 79$ in terms of  trigonometric ratios  of angles between 0° and 45​° is $\csc 11+\tan 11$.

Step-by-step explanation:

We have,

$\sec79+\cot 79$

To express  $\sec79+\cot 79$ in terms of  trigonometric ratios  of angles between 0° and 45​°.

∴ $\sec79+\cot 79$

= $\sec (90-11)+\cot (90-11)$

Using the trigonometric identity,

$\sec (90-A)=\csc A$ and

$\cot (90-A)=\tan A$

= $\csc 11+\tan 11$

∴ $\sec79+\cot 79$ = $\csc 11+\tan 11$

Thus, express  $\sec79+\cot 79$ in terms of  trigonometric ratios  of angles between 0° and 45​° is $\csc 11+\tan 11$.