Question

Express sin 67° + cos 75° in terms of trigonometric ratios of angles between 0° and 45° ​

Answer 1

cos(33°) + sin(15°)

Step-by-step explanation:

QUESTION :-

Express (sin 67° + cos 75°) in terms of trigonometric ratios of angles between 0° and 45°.

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SOLUTION :-

sin(67°) + cos(75°)

=> sin(90° - 33°) + cos (90° - 15°)

=> cos(33°) + sin(15°)

[b'coz, sin(90°- θ)= cos(θ) ; cos(90°- θ) = sin(θ)]

Hence,

The answer is cos(33°) + sin(15°).

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Hope it helps.

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