Express sin 67degree +cos 75degreein terms of trigonomertric ratios of 0degree and 45 degree
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Solution :
Given sin 67° + cos 75°
= sin( 90 - 23 ) + cos ( 90 - 15 )
= cos 23° + sin 15°
[ Since , sin( 90 - A ) = cosA ,
Cos( 90 - A ) = sinA ]
•••••
Given sin 67° + cos 75°
= sin( 90 - 23 ) + cos ( 90 - 15 )
= cos 23° + sin 15°
[ Since , sin( 90 - A ) = cosA ,
Cos( 90 - A ) = sinA ]
•••••
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0
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