Question

Express sin x/2 Cos 3x/2 as a sum or difference of trigonometric function.​

Answer 1

Answer:

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Step-by-step explanation:

Fomula used: sin x cos y = [sin (x+y) + sin (x-y) whole divided by 2]

Then,

sin x/2 cos 3x/2 = [ sin ( x/2 + 3x/2) + sin (x/2 - 3x/2) ] ÷ 2

= [sin ( 2x ) + sin (-x) ] ÷ 2. *****

= [2 sin x cos x - sin x] ÷ 2

Answer : ( sin x cos x) - ( sin x / 2)

OR **** Another answer can be

[ sin (2x) - sin (x) ] ÷ 2