Question

express sin x in terms of tan x

Answer 1

$tanx = \frac{sinx}{cosx}$
$sinx= tanx*cosx$
$sinx = tanx * \frac{1}{secx}$

From the identity
1 + tan²x = sec²x
$\frac{+}{-} \sqrt{1+tan^2} = secx$

$sinx = tanx * \frac{1}{ \frac{+}{-} \sqrt{tan^2+1} }$

$sinx = \frac{tanx}{ \frac{+}{-} \sqrt{tan^2+1} }$

Answer 2

Answer:

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Step-by-step explanation:

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