express sin3A in terms of sinA
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Answer:
Explanation:
Trigonometric function of sin 3A in terms of sin A is also known as one of the double angle formula.
If A is a number or angle then we have, sin 3A = 3 sin A - 4 sin^3 A.
Now we will proof the above multiple angle formula step-by-step.
Proof: sin 3A
= sin (2A + A)
= sin 2A cos A + cos 2A sin A
= 2 sin A cos A ∙ cos A + (1 - 2 sin^2 A) sin A
= 2 sin A (1 - sin^2 A) + sin A - 2 sin^3 A
= 2 sin A - 2 sin^3 A + sin A - 2 sin^3 A
= 3 sin A - 4 sin^3 A
Therefore, sin 3A = 3 sin A - 4 sin^3 A Proved
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