Question

express sin4 theta\sin theta in terms of cos cube theta and cos theta

Answer 1

Answer:

By de Moivre's formula we have:

cosnθ+isinnθ=(cosθ+isinθ)n

So:

cos4θ+isin4θ

=(cosθ+isinθ)4

=

Answer 2

Answer:

We have, sin12θ + sin4θ sin 2 (6θ) + sin 2 (2θ) 2sin 6θcos 6θ + 2sin 2θcos 2θ 2sin 2 (3θ)cos 6θ + 4sinθcosθcos 2θ 4sin 3θcos 3θcos ...