Express sin75 cos 15-cos75sin15 as a single trigonometric function of a positive acute angle
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2
sin75cos15-cos75sin15
= sin(75-15)
=sin60
[since sinAcosB-cosAsinB=sin(A-B)]
= sin(75-15)
=sin60
[since sinAcosB-cosAsinB=sin(A-B)]
Answered by
1
Since , sin(A-B) = sinAcosB-cosAsinB
So , it'll become , sin(75°-15°) = sin60° = 1/√2
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