Question

express sinA/2and cosA/2 in terms of cosA​

Answer 1

Answer:

cosA=

1−sin

2

A

→(1)

as, cos

2

θ+sin

2

θ=1

tanA=

cosA

sinA

=

1−sin

2

A

sinA

( from (1) )

& secA=

cosA

1

=

1−sin

2

A

1

( From (1) )

so, cosA=

1−sin

2

A

,tanA=

1−sin

2

A

sinA

& secA=

1−sin

2

A

1

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