Express sinA anct secA in terms of cotA'
wixmatwishwa:
whats mean "anct"
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we have sinA; and secA
where secA can be written as 1/ cosA
where sinA x 1/ cosA
= sinA/cosA (resiprcol of this is)
= cosA /sinA (which means)
= cotA
and the final answer is cotA
where secA can be written as 1/ cosA
where sinA x 1/ cosA
= sinA/cosA (resiprcol of this is)
= cosA /sinA (which means)
= cotA
and the final answer is cotA
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