Question

express sinA ,cosA, cosecA, and sec A in terms of cot A.

Answer 1

using the identity cosec^2A-cot^2A=1
we get cosec^2A=1+cot^2a
1/sin^2A=1+cot^2A
sin^2A=1/1+cot^2A
sinA=(1/1+cot^2A)^1/2

using identity sec^2A-tan^2A=1
we get
sec^2A=1+tan^2A
sec^2A=1+1/cot^2A
sec^2A=cot^2A+1/cot^2A
secA=(cot^2A+1/cot^2A)^1/2 .

Answer 2

sec^2A=1+tan^2A 
sec^2A=1+1/cot^2A 
sec^2A=cot^2A+1/cot^2A 
secA=(cot^2A+1/cot^2A)^1/2