Question

express sinA in term cosA​

Answer 1

There you go :- 

cos a = square root of (1- square of sin a) 

tan = sin a / cos a = sin a/(square root of (1- square of sin a)) 

cosec a = 1/sin a 

sec a = 1/cos a = 1/(square root of (1- square of sin a)) 

cot a = cos a /sin a = (square root of (1- square of sin a))/sin a

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Answer 2

Answer:

Step-by-step explanation:

cos a = square root of (1- square of sin a) 

tan = sin a / cos a = sin a/(square root of (1- square of sin a)) 

cosec a = 1/sin a 

sec a = 1/cos a = 1/(square root of (1- square of sin a)) 

cot a = cos a /sin a = (square root of (1- square of sin a))/sin a