Question

Express SinA in terms of CosA

Answer 1

Answer:

cos a = square root of (1- square of sin a) 

tan = sin a / cos a = sin a/(square root of (1- square of sin a)) 

cosec a = 1/sin a 

sec a = 1/cos a = 1/(square root of (1- square of sin a)) 

cot a = cos a /sin a = (square root of (1- square of sin a))/sin a

Answer 2

$\huge\mathbb\red{SOLUTION}\green{:-}$

$\huge\bold\orange{We~Know~that}$

Sin²theta + Cos²theta = 1

Sin² A + Cos² A = 1

Sin² A = 1 - Cos² A

$\huge\bold\pink{→}$ Sin A = √1 - Cos² A

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