Question

Express sinA in terms of secA

Answer 1

Answer:

look at the application of formula

Answer 2

Answer:

sinA = tanA × cos A

= tanA × 1/secA

= tanA / secA.....i)

tan²A = sec²A - 1

tanA =√sec²A-1

Put tanA √sec²A-1 in i)

sin A = √sec²A - 1 / secA