Math, asked by femountukhsh, 1 year ago

Express sinA in Terms of secA.

Answers

Answered by ARoy

1

sin²A+cos²A=1
or, sin²A=1-cos²A
or, sin²A=1-1/sec²A
or, sin²A=(sec²A-1)/sec²A
∴, sinA=√(sec²A-1)/secA

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