Express Tan A in terms of Sin A.
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tanA=sinA/√1-sin square A
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We know that Sin²A+Cos²A=1
So, Cos²A= 1-Sin²A
=> CosA= √1-Sin²A
We know that Tan A=SinA/CosA ..................Eq.(1)
On substituiting the value of Cos A in Eq.(1) we get
Tan A = SinA/√1-Sin²A
Thanks!!!
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