Question

Express tan theta in terms of sec theta.​

Answer 1

hope it helps you......

Answer 2

As we know,

$\tan( \alpha ) = \sin( \alpha ) \div \cos( \alpha )$

so,

$\cos( \alpha ) = 1 \div \sec( \alpha )$

putting the value in previous eq.

$\tan( \alpha ) = \sin( \alpha ) \div 1 \div \sec( \alpha )$

$\tan( \alpha ) = \sin( \alpha ) \times \sec( \alpha )$

Hope it helps....

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