express tanA in terms of sinA
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Answered by
48
tanA= SinA/CosA
Sin²A+Cos²A=1
CosA=√(1-Sin²A)
So tan A= SinA/√(1-Sin²A)
Sin²A+Cos²A=1
CosA=√(1-Sin²A)
So tan A= SinA/√(1-Sin²A)
Answered by
8
tan A=sin A/_/1_sin^2A
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