express that √3-√2 is an irrational number
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Any number subtracted from or added to an irrational number is always an irrational number.
Example: a - b
Here if b is an irrational number and a is a rational number then the end result a - b is also irrational.
Example: a - b
Here if b is an irrational number and a is a rational number then the end result a - b is also irrational.
vanshu7:
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Answered by
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Hi friend!!
Let √3 - √2 is a rational number.
A rational number can be written in the form of p/q.
√3 - √2 = p/q
Squaring on both sides,
(√3-√2)² = (p/q)²
√3²+√2²-2(√3)(√2) = p²/q²
3+2-2√6 = p²/q²
5-2√6 = p²/q²
2√6 = 5 - p²/q²
2√6 = (5q²-p²)/q²
√6 = (5q²-p²)/2q
p,q are integers then (5q²-p²)/2q is a rational number.
Then √6 is also a rational number.
But this contradicts the fact that √6 is an irrational number.
So,our supposition is false.
Therefore,√3-√2 is an irrational number.
Hope it helps
Let √3 - √2 is a rational number.
A rational number can be written in the form of p/q.
√3 - √2 = p/q
Squaring on both sides,
(√3-√2)² = (p/q)²
√3²+√2²-2(√3)(√2) = p²/q²
3+2-2√6 = p²/q²
5-2√6 = p²/q²
2√6 = 5 - p²/q²
2√6 = (5q²-p²)/q²
√6 = (5q²-p²)/2q
p,q are integers then (5q²-p²)/2q is a rational number.
Then √6 is also a rational number.
But this contradicts the fact that √6 is an irrational number.
So,our supposition is false.
Therefore,√3-√2 is an irrational number.
Hope it helps
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