Math, asked by sant23, 1 year ago

Express the complex number
(1 - i) + (-1 + 6i) in the standard form a + ib.


NikhilSinghJi: (1-i)/(1+i)

=(1-i)*(1-i)/(1+i)*(1-i)

=(1-i)2/ (1)2 - (i)2

=1+i2-2i /1-i2

=-2i / 2 = -i

so, a+ib = 0-i

so, a = 0 b=-1

Answers

Answered by sanran
8

Answer: 0 + 5i


Step-by-step explanation:


=(1 - i) + (-1 + 6i)


= 1 - i -1 + 6i


= 1 - 1 - i + 6i


= 0 + 5i, which is the required form.


Complex equation should be this form only a+bi format

Answered by Thatsomeone
6
Hey user



Here is your answer



( 1 - i ) + ( - 1 + 6i )



= 1 - i - 1 + 6i



= ( 1 - 1 ) + ( 6 - 1 )i



= 0 + 5i



Hence



( 1 - i ) + ( - 1 + 6i ) = 0 + 5i



Thank you.



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