Express the complex number
(1 - i) + (-1 + 6i) in the standard form a + ib.
Answers
Answered by
8
Answer: 0 + 5i
Step-by-step explanation:
=(1 - i) + (-1 + 6i)
= 1 - i -1 + 6i
= 1 - 1 - i + 6i
= 0 + 5i, which is the required form.
Complex equation should be this form only a+bi format
Answered by
6
Hey user
Here is your answer
( 1 - i ) + ( - 1 + 6i )
= 1 - i - 1 + 6i
= ( 1 - 1 ) + ( 6 - 1 )i
= 0 + 5i
Hence
( 1 - i ) + ( - 1 + 6i ) = 0 + 5i
Thank you.
Here is your answer
( 1 - i ) + ( - 1 + 6i )
= 1 - i - 1 + 6i
= ( 1 - 1 ) + ( 6 - 1 )i
= 0 + 5i
Hence
( 1 - i ) + ( - 1 + 6i ) = 0 + 5i
Thank you.
Similar questions
=(1-i)*(1-i)/(1+i)*(1-i)
=(1-i)2/ (1)2 - (i)2
=1+i2-2i /1-i2
=-2i / 2 = -i
so, a+ib = 0-i
so, a = 0 b=-1